[pptp-server] LAN to LAN pptp connection (ipchains involved)
Jeffrey Hummel
jhummel at fulltilt.com
Tue Aug 8 10:01:18 CDT 2000
Thanks for that, but thats not the problem, otherwise I wouldn't be able to
access the PPTP server inside the Cisco FW. That works fine - I currently
have over 100 PPTP windoze and Linux clients running without a hitch. Cisco
firewall I know, its Ipchains that gets confusing to me.
-J
-----Original Message-----
From: gord at amador.ca [mailto:gord at amador.ca]
Sent: Tuesday, August 08, 2000 10:56 AM
To: Jeffrey Hummel; pptp-server at lists.schulte.org
Subject: Re: [pptp-server] LAN to LAN pptp connection (ipchains
involved)
Hi Jeffery:
One thing to watch for is the Cicso firewall....it has to allow both TCP
port 1723 and protocol 47 (gre) through. The gre is a separate access
list....I don't have it handy, but if you have CCO access Cisco TAC will set
you up.
Hope this is helpful
Gord Belsey
----- Original Message -----
From: Jeffrey Hummel <jhummel at fulltilt.com>
To: <pptp-server at lists.schulte.org>
Sent: Monday, August 07, 2000 1:59 PM
Subject: [pptp-server] LAN to LAN pptp connection (ipchains involved)
> Hello All,
>
> I have been running Poptop and WinNT PPTP and a linux pptp client rather
> flawlessly several ways. My next solution is a PPTP LAN to LAN
connection.
> I have tried several ways to configure PPTP and ipchains but I believe it
is
> an ipchains problem where I get stupid. Here is my scenario:
>
> Windoze LAN --> Linux IPCHAINS FW / PPTP client --> Internet --> Cisco
rules
> based FW --> PPTP Server (WinNT)
>
> If I don't have any ipchains rules running, the Linux pptp client works
> great and from that box I can see the entire PPTP server LAN. What I want
> to do is route all of the traffic from my Windoze LAN thru the PPTP server
> LAN. I have said to accept the PPTP client and server ip range and also
the
> PPTP serve ip lan range. No good. I think I am missing something w/
PPTP.
> I can give you my ipchains script if you want.
>
> Anyone interested in tackling this one with me? I would appreciate any
and
> all help as usual.
>
> -Jeff
>
>
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